The dense point reticle sight in the picture first appeared in the steel Unertl high-magnification optical sight in the Vietnam War.In the early days, people used different reticles, but all because of the single function or too complex, it is not easy to use On the surface, this kind of sight has many small dots for positioning distributed on the crosshair of the sight to measure distance. This division is the mildot scope.
Now there are many countries’ military and police law enforcement agencies and some hunting scopes, all of which use this kind of reticle
In the military, the surroundings are regarded as a perfect circle. The perfect circle is divided into 6400 equal parts. In the scope, the distance between the two points is exactly that the person represents one equal part, that is, 1/6400.
Such as: a division of 10,000 meters away. It can be calculated by the following formula: 3.1415927×20000/6400=9.8174771875 meters. It is about 10 meters.
Such as: a division of 1000 meters away. It can be calculated by the following formula: 3.1415927×2000/6400=0.98174771875 meters. It is about 1 meter.
It is very simple to calculate the distance of the target. You can refer to the following formula: Target length or height / density X 1000
Let’s use the example in this picture to estimate the distance: At this time, the target is 100 meters away from the shooter.
In the picture, we evaluate according to the height of a Middle Eastern person. The average height of Europeans and Americans is 1.7 meters. In the picture, the height of the character occupies about 1.7 squares in the picture, namely
1.7 density. Now let’s calculate: formula: height / density x 1000
1.7/1.7×1000=1000 meters (yards)
What needs to be explained here is: in the actual scope design, a large grid in the picture is often not a dense position. Because the author has never used a real LEUPOLD scope, it is calculated based on one grid and one dense position. In fact, one grid in the picture may have five dense positions. In this way, the person in that picture may be about 200 meters away from the shooter.
Below we use an actual sight to measure. Sight is VPOINT 3. 5-10X40. As shown below:
According to the data provided by the factory, this sight is at a distance of 100 meters and the scope of sight is 103 meters wide. So we drew a picture. In the picture. The black line represents the reticle of the scope, the reticle point, and the outer black circle is the imaging boundary of the scope. The diameter of this circle is 103 meters.
The red square in the picture is drawn for the convenience of users to read the picture. A red grid represents 1 meter in reality.
In the reticle, the distance between every two black dots approximately represents the actual distance of 100 meters is 0.4 meters. According to the formula, we know that in the international standard, a density unit is 0.1 meter at 100 meters. Therefore, each large grid of this scope is equivalent to 4 dense positions.
I tested the distance with a scope. I first aimed at a building not far away. Because each floor of the building has the same height, I used this as a distance measurement. In the distant building, the lower edge of one of the windows and the lower edge of the window on the upper floor accounted for approximately in the scope. The distance of about 5 black dots (about 20 dense). According to our common knowledge of construction, the height of a residential house is generally 2.8 meters, so I apply the formula below:
2.8 (m) / 20 (closed position) X 1000 = 140 meters.
It can be seen that the distant window is about 140 meters away from my office.
I did another test on the nearest place. I checked the nearest window, and it happened to be pasted with an A4 paper. I measured it, and the narrowest width of the A4 paper is exactly the same as the spacing of about three black dots in the sight, and it’s about 7 dense.
Because the narrow size of A4 paper is the international standard size of 0.21 meters. I started to make a calculation:
0.21(m) / 7 x 1000 = 30(m)
finally calculated that the distance between me and the piece of paper was 30 meters.
Actually I used a laser rangefinder to measure it before. My exact distance from the red is approximately: 29.3 meters.
This shows that the distance is measured with dense points. In addition, the reasonable dense point distribution on the reticle of the VPOINT scope. Ranging is relatively accurate.
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